WAEC 2020 · Paper 1 · Q37

Find the sum of the interior angles of a pentagon.

Worked solution (try it first)

The interior angles of an $n$ -sided polygon add up to $(n - 2) \times 180^\circ$ .
For a pentagon, $n = 5$ : $(5 - 2) \times 180^\circ = 540^\circ$ , option C.