WAEC 2020 · Paper 1 · Q42

xx 6.20 6.85 7.50
yy 3.90 5.20 6.50

The points on a linear graph are as shown in the table. Find the gradient of the line.

Worked solution (try it first)
  1. Use any two points, for example the first two: the change in yy is 5.20−3.90=1.305.20 - 3.90 = 1.30.
  2. The change in xx is 6.85−6.20=0.656.85 - 6.20 = 0.65.
  3. Gradient =1.300.65=2= \frac{1.30}{0.65} = 2, option B.

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