WAEC 2020 · Paper 1 · Q43

In the diagram, OO is the centre of the circle. PQPQ and RSRS are tangents to the circle at the ends of a diameter. Find the value of (m+n)∘(m + n)^\circ.

m°n°OPQRS
Worked solution (try it first)
  1. Each of mm and nn is an angle between a tangent and a chord, so each equals the angle in the alternate segment: they are the two angles of the triangle at the ends of the diameter, taken crosswise.
  2. The third angle of the triangle stands on the diameter, so it is 90∘90^\circ (angle in a semicircle).
  3. So the two angles at the ends of the diameter add up to 180∘−90∘=90∘180^\circ - 90^\circ = 90^\circ, and m+n=90∘m + n = 90^\circ, option B.

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