WAEC 2020 · Paper 2 · Q7

  1. (a)

    The diagram shows a wooden structure in the form of a cone, mounted on a hemispherical base. The vertical height of the cone is 48 m48\text{ m} and the base radius is 14 m14\text{ m}. Calculate, correct to three significant figures, the surface area of the structure. [Take π=227]\left[\text{Take }\pi = \frac{22}{7}\right]

    48 m14 mLMN
  2. (b)

    Five years ago, Musah was twice as old as Sesay. If the sum of their ages is 100, find Sesay's present age.

Worked solution (try it first)

(a)

  1. The surface of the structure is the curved surface of the cone plus the curved surface of the hemisphere (the flat circle where they join is hidden).
  2. Slant height of the cone: l=482+142l = \sqrt{48^2 + 14^2}
    =2304+196= \sqrt{2304 + 196}
    =2500= \sqrt{2500}
    =50 m= 50\text{ m}.
  3. Curved surface of the cone =πrl= \pi r l
    =227×14×50= \frac{22}{7} \times 14 \times 50
    =2200 m2= 2200\text{ m}^2.
  4. Curved surface of the hemisphere =2πr2= 2\pi r^2
    =2×227×196= 2 \times \frac{22}{7} \times 196
    =1232 m2= 1232\text{ m}^2.
  5. Total =2200+1232=3432 m2= 2200 + 1232 = 3432\text{ m}^2.
  6. Correct to three significant figures: 3430 m23430\text{ m}^2.

(b)

  1. Let Sesay's age now be xx years.
  2. Since the ages add up to 100, Musah is 100−x100 - x.
  3. Five years ago they were x−5x - 5 and 95−x95 - x, and Musah was twice as old: 95−x=2(x−5)95 - x = 2(x - 5).
  4. Expand: 95−x=2x−1095 - x = 2x - 10.
  5. So 3x=1053x = 105 and x=35x = 35.
  6. Sesay is 35 years old.

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