WAEC 2021 · Paper 1 · Q8

What number should be subtracted from the sum of 2162\frac16 and 27122\frac{7}{12} to give 3143\frac14?

Worked solution (try it first)
  1. Add the two numbers.
  2. The LCD of 6 and 12 is 12: 2212+2712=49122\frac{2}{12} + 2\frac{7}{12} = 4\frac{9}{12}
    =434= 4\frac34.
  3. The number is what you take from 4344\frac34 to leave 3143\frac14: 434−314=124=1124\frac34 - 3\frac14 = 1\frac24 = 1\frac12, option B.

Report a problem with this question