WAEC 2021 · Paper 2 · Q5

  1. (a)
    Child's name Ann Afia Kojo Nuno Akosua
    Percentage share 5 15 10 45 25

    A man shared his property among his children as shown. Represent the information on a pie chart.

    Model answer
    Ann 18°Afia54°Kojo 36°Nuno162°Akosua90°

    Each 1%1\% is 3.6∘3.6^\circ of the circle, so the angles are Ann 18∘18^\circ, Afia 54∘54^\circ, Kojo 36∘36^\circ, Nuno 162∘162^\circ and Akosua 90∘90^\circ (total 360∘360^\circ). Draw each sector with a protractor and label it.

  2. (b)

    A box contains 5 red, 3 green and 4 blue identical beads. Calculate the probability that a girl takes away two red beads, one after the other, from the box.

Worked solution (try it first)

(a)

  1. The whole circle, 360∘360^\circ, is 100%100\%, so 1%=3.6∘1\% = 3.6^\circ.
  2. Ann 5×3.6∘=18∘5 \times 3.6^\circ = 18^\circ, Afia 54∘54^\circ, Kojo 36∘36^\circ, Nuno 162∘162^\circ, Akosua 90∘90^\circ.
  3. Check: 18+54+36+162+90=36018 + 54 + 36 + 162 + 90 = 360.
  4. Draw the sectors with a protractor and label each with the child's name and angle.

(b)

  1. There are 5+3+4=125 + 3 + 4 = 12 beads.
  2. The first bead is red with probability 512\frac{5}{12}.
  3. It is taken away, so 11 beads remain, 4 of them red: the second is red with probability 411\frac{4}{11}.
  4. Both red: 512×411=20132\frac{5}{12} \times \frac{4}{11} = \frac{20}{132}
    =533= \frac{5}{33}.

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