WAEC 2022 · Paper 1 · Q21

In the diagram, ∠POQ=150∘\angle POQ = 150^\circ and the radius of the circle PSQRPSQR is 4.2 cm4.2\text{ cm}. Find the length of the minor arc PRQPRQ. [Take π=227]\left[\text{Take }\pi = \frac{22}{7}\right]

4.2 cm150°OPQSR
Worked solution (try it first)
  1. Arc length =θ360×2πr= \frac{\theta}{360} \times 2\pi r.
  2. The circumference is 2×227×4.2=26.42 \times \frac{22}{7} \times 4.2 = 26.4 cm.
  3. The minor arc is 150360\frac{150}{360} of it: 512×26.4=11\frac{5}{12} \times 26.4 = 11 cm, option A.

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