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WAEC 2022 · Paper 1 · Q26

The length of a rectangle is 10 cm10\text{ cm}. If its perimeter is 28 cm28\text{ cm}, find the area.

Worked solution (try it first)
  1. Half the perimeter is length + width: 28÷2=1428 \div 2 = 14 cm.
  2. So the width is 14−10=414 - 10 = 4 cm.
  3. Area =10×4=40 cm2= 10 \times 4 = 40\text{ cm}^2, option B.

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