WAEC 2022 · Paper 1 · Q35

The diagram shows triangle PQRPQR inscribed in a circle. PSPS is a tangent to the circle at PP, ∠QPR=58∘\angle QPR = 58^\circ and ∠RPS=73∘\angle RPS = 73^\circ. Find ∠PRQ\angle PRQ.

58°73°PQRS
Worked solution (try it first)
  1. The angle between a tangent and a chord equals the angle in the alternate segment.
  2. So ∠PQR=∠RPS=73∘\angle PQR = \angle RPS = 73^\circ.
  3. The angles of triangle PQRPQR add up to 180∘180^\circ: ∠PRQ=180∘−58∘−73∘\angle PRQ = 180^\circ - 58^\circ - 73^\circ.
  4. So ∠PRQ=49∘\angle PRQ = 49^\circ, option A.

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