WAEC 2022 · Paper 1 · Q36

In the diagram, triangle MNRMNR is inscribed in circle MNRMNR and PQPQ is a straight line. If ∠MRN=41∘\angle MRN = 41^\circ and ∠PMR=141∘\angle PMR = 141^\circ, find ∠QNR\angle QNR.

141°41°MNRPQ
Worked solution (try it first)
  1. PMNQPMNQ is a straight line: ∠RMN=180∘−141∘\angle RMN = 180^\circ - 141^\circ
    =39∘= 39^\circ.
  2. ∠QNR\angle QNR is an exterior angle of triangle MNRMNR, so it equals the sum of the two interior opposite angles.
  3. So ∠QNR=39∘+41∘\angle QNR = 39^\circ + 41^\circ
    =80∘= 80^\circ, option B.

Report a problem with this question