WAEC 2022 · Paper 1 · Q46

The straight line y=mx−4y = mx - 4 passes through the point (−4,16)(-4, 16). Calculate the gradient of the line.

Worked solution (try it first)
  1. The point is on the line, so put x=−4x = -4 and y=16y = 16 into y=mx−4y = mx - 4: 16=−4m−416 = -4m - 4.
  2. Add 4 to both sides: 20=−4m20 = -4m.
  3. Divide by −4-4: m=−5m = -5, option A.

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