WAEC 2022 · Paper 2 · Q6

The graph shows the relation of the form y=mx2+nx+ry = mx^2 + nx + r, where mm, nn and rr are constants. Using the graph:

xy−8−6−4−22468−70−60−50−40−30−20−101020PQ
Scale: 2 cm to 2 units on the x-axis and 2 cm to 10 units on the y-axis.
  1. (a)

    State the scale used on both axes.

    Show the answer

    xx: 2 cm to 2 units; yy: 2 cm to 10 units

  2. (b)

    Find the values of mm, nn and rr.

    Separate values with commas, e.g. 3, −2

  3. (c)

    Find the gradient of the line through PP and QQ.

  4. (d)

    State the range of values of xx for which y>0y > 0.

    Show the answer

    −2<x<4-2 < x < 4

Try it on a graph

Drag-free check: does y = −x² + 2x + 8 really pass through P and Q? Edit the constants to see.

Worked solution (try it first)

(a)

  1. On the xx-axis, 2 cm represents 2 units.
  2. On the yy-axis, 2 cm represents 10 units.

(b)

  1. The curve crosses the xx-axis at x=−2x = -2 and x=4x = 4, so (x+2)(x + 2) and (x−4)(x - 4) are factors.
  2. It has a highest point, so the x2x^2 term is negative: y=−(x+2)(x−4)=−x2+2x+8y = -(x + 2)(x - 4) = -x^2 + 2x + 8.
  3. So m=−1m = -1, n=2n = 2 and r=8r = 8.
  4. (Check: the curve crosses the yy-axis at r=8r = 8 ✓.)

(c)

  1. From the graph, P(−5,−27)P(-5, -27) and Q(3,5)Q(3, 5).
  2. The rise is 5−(−27)=325 - (-27) = 32 and the run is 3−(−5)=83 - (-5) = 8, so the gradient is 328=4\frac{32}{8} = 4.

(d)

  1. y>0y > 0 where the curve is above the xx-axis, between the roots: −2<x<4-2 < x < 4.

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