WAEC 2022 · Paper 2 · Q7

  1. (a)

    A man purchased 180 copies of a book at ₦250.00 each. He sold yy copies at ₦300.00 each and the rest at a discount of 5 kobo in the Naira of the cost price. If he made a profit of ₦7,125.00, find the value of yy.

  2. (b)

    A trader bought xx bags of rice at a cost c=24x+103c = 24x + 103 and sold them at a price s=33x−x220s = 33x - \frac{x^2}{20}. (i) Find the expression for the profit. (ii) If 20 bags of rice were sold, calculate the percentage profit.

Worked solution (try it first)

(a)

  1. Cost =180×250=₦45,000= 180 \times 250 = ₦45,000.
  2. A discount of 5 kobo in the naira is 5%5\%, so the rest sold at 0.95×250=₦237.500.95 \times 250 = ₦237.50 each.
  3. Sales =300y+237.5(180−y)=62.5y+42 750= 300y + 237.5(180 - y) = 62.5y + 42\,750.
  4. Profit: 62.5y+42 750−45 000=712562.5y + 42\,750 - 45\,000 = 7125, so 62.5y=937562.5y = 9375 and y=150y = 150.

(b)(i)

  1. Profit =s−c= s - c
    =33x−x220−(24x+103)= 33x - \frac{x^2}{20} - (24x + 103)
    =9x−x220−103= 9x - \frac{x^2}{20} - 103.

(ii)

  1. At x=20x = 20: cost =24(20)+103=583= 24(20) + 103 = 583, sales =660−20=640= 660 - 20 = 640, profit =57= 57.
  2. Percentage profit =57583×100%= \frac{57}{583} \times 100\%
    ≈9.78%\approx 9.78\%.

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