WAEC 2022 · Paper 2 · Q8

  1. (a)

    In a class of 60 students, 30 read Literature and 35 read Government. All the students read at least one of the subjects. If a student is selected at random from the class, find the probability that the student reads only one subject.

  2. (b)

    A sector of angle 220∘220^\circ is removed from a thin circular metal sheet of radius 63 cm63\text{ cm}. It is then folded with the straight edges meeting to form a right circular cone. Calculate, correct to one decimal place, the: (i) base radius; (ii) volume, of the cone. [Take π=227]\left[\text{Take }\pi = \frac{22}{7}\right]

    Separate values with commas, e.g. 3, −2

Worked solution (try it first)

(a)

  1. Every student reads at least one subject, so 30+3530 + 35 counts the students who read both twice: 30+35−x=6030 + 35 - x = 60, and x=5x = 5 read both.
  2. Literature only =30−5=25= 30 - 5 = 25.
  3. Government only =35−5=30= 35 - 5 = 30.
  4. Only one subject: 25+30=5525 + 30 = 55 students, so P=5560=1112P = \frac{55}{60} = \frac{11}{12}.

(b)(i)

  1. When the sector is folded into a cone, its arc becomes the circumference of the base.
  2. Arc length =220360×2π×63= \frac{220}{360} \times 2\pi \times 63 and base circumference =2πr= 2\pi r, so r=220360×63=38.5r = \frac{220}{360} \times 63 = 38.5 cm.

(ii)

  1. The radius of the sheet, 63 cm, becomes the slant height of the cone.
  2. Height: h=632−38.52h = \sqrt{63^2 - 38.5^2}
    =3969−1482.25= \sqrt{3969 - 1482.25}
    =2486.75= \sqrt{2486.75}
    ≈49.867\approx 49.867 cm.
  3. Volume =13πr2h= \frac13\pi r^2 h
    =13×227×38.52×49.867= \frac13 \times \frac{22}{7} \times 38.5^2 \times 49.867
    ≈77 435.6 cm3\approx 77\,435.6\text{ cm}^3.

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