WAEC 2023 · Paper 1 · Q3

Solve 25x÷2x=21052^{5x} \div 2^x = \sqrt[5]{2^{10}}.

Worked solution (try it first)
  1. Dividing powers of 2, subtract the indices: 25x÷2x=24x2^{5x} \div 2^x = 2^{4x}.
  2. A fifth root divides the index by 5: 2105=22\sqrt[5]{2^{10}} = 2^2.
  3. So 4x=24x = 2 and x=12x = \frac12, option C.

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