WAEC 2023 · Paper 1 · Q4

Indices & standard form

Solve $1 + \sqrt[3]{x - 3} = 4$ .

Worked solution (try it first)

Subtract 1 from both sides: $\sqrt[3]{x - 3} = 3$ .
Cube both sides to undo the cube root: $x - 3 = 27$ .
Add 3: $x = 30$ , option C.

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