WAEC 2023 · Paper 1 · Q47

Simplify 312+103−633\sqrt{12} + 10\sqrt3 - \dfrac{6}{\sqrt3}.

Worked solution (try it first)
  1. Take out the square factor: 312=3×233\sqrt{12} = 3 \times 2\sqrt3, which is 636\sqrt3.
  2. Rationalise: 63=633\dfrac{6}{\sqrt3} = \dfrac{6\sqrt3}{3}, which is 232\sqrt3.
  3. Combine: 63+103−23=1436\sqrt3 + 10\sqrt3 - 2\sqrt3 = 14\sqrt3, option A.

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