WAEC 2023 · Paper 2 · Q7

  1. (a)

    Aman spent 13\frac13 of his income on rent, 16\frac16 of the income in a fast food shop and 34\frac34 of the remaining amount was saved in a bank. If he had ₦125,000.00 left, find: (i) his income; (ii) the amount saved in the bank.

    Separate values with commas, e.g. 3, −2

  2. (b)

    Solve: 2+3x5−1−7x3<2x+9\dfrac{2 + 3x}{5} - \dfrac{1 - 7x}{3} < 2x + 9.

    Show the answer

    x<677x < \frac{67}{7}

Worked solution (try it first)

(a)

  1. Rent and food take 13+16=12\frac13 + \frac16 = \frac12 of his income, leaving 12\frac12.
  2. He saves 34\frac34 of that: 34×12=38\frac34 \times \frac12 = \frac38.
  3. What's left is 12−38=18\frac12 - \frac38 = \frac18 of his income.

(i)

  1. 18\frac18 of his income is ₦125,000, so his income is 8×125 000=₦1,000,0008 \times 125\,000 = ₦1,000,000.

(ii)

  1. Saved: 38×1 000 000=₦375,000\frac38 \times 1\,000\,000 = ₦375,000.

(b)

  1. Multiply every term by 15 (the LCM of 5 and 3): 3(2+3x)−5(1−7x)<15(2x+9)3(2 + 3x) - 5(1 - 7x) < 15(2x + 9), so 6+9x−5+35x<30x+1356 + 9x - 5 + 35x < 30x + 135.
  2. Then 44x+1<30x+13544x + 1 < 30x + 135, so 14x<13414x < 134 and x<677x < \frac{67}{7} (that is, x<947x < 9\frac47).

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