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WAEC 2024 · Paper 1 · Q15

Make RR the subject of the relation V=πl(R2−r2)V = \pi l(R^2 - r^2).

Worked solution (try it first)
  1. Divide both sides by πl\pi l: Vπl=R2−r2\frac{V}{\pi l} = R^2 - r^2.
  2. Add r2r^2: R2=Vπl+r2R^2 = \frac{V}{\pi l} + r^2.
  3. Take the square root: R=Vπl+r2R = \sqrt{\dfrac{V}{\pi l} + r^2}, option A.

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