JAMB 1987 · UME · Q19

If PP varies inversely as VV and VV varies directly as R2R^2, find the relationship between PP and RR, given that R=7R = 7 when P=2P = 2.

Worked solution (try it first)
  1. P=cVP = \dfrac{c}{V} and V=mR2V = mR^2, so P=cmR2P = \dfrac{c}{mR^2}: PP varies inversely as R2R^2.
  2. So P=kR2P = \dfrac{k}{R^2}, which means PR2=kPR^2 = k.
  3. Put in R=7R = 7, P=2P = 2: k=2×49=98k = 2 \times 49 = 98.
  4. So PR2=98PR^2 = 98, option B.

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