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JAMB 1987 · UME · Q20

Make yy the subject of the formula Z=x2+1y3Z = x^2 + \dfrac{1}{y^3}.

Worked solution (try it first)
  1. Subtract x2x^2 from both sides: 1y3=Z−x2\frac{1}{y^3} = Z - x^2.
  2. Turn both sides upside down: y3=1Z−x2y^3 = \frac{1}{Z - x^2}.
  3. Take the cube root: y=1(Z−x2)1/3y = \dfrac{1}{(Z - x^2)^{1/3}}, option C.

Also set as JAMB 2018 · UTME · Q23

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