JAMB 1994 · UME · Q30

Calculate the perimeter, in cm, of a sector of a circle of radius 8 cm and angle 45∘45^\circ.

Worked solution (try it first)
  1. The circumference is 2π×8=16π2\pi \times 8 = 16\pi cm.
  2. The arc is 45360=18\frac{45}{360} = \frac18 of it: 18×16π=2π\frac18 \times 16\pi = 2\pi cm.
  3. The perimeter adds both radii: 8+8+2π=16+2π8 + 8 + 2\pi = 16 + 2\pi cm, option C.

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