JAMB 1997 · UME · Q28

A chord of a circle of diameter 42 cm subtends an angle of 60∘60^\circ at the centre. Find the length of the minor arc. [π=227]\left[\pi = \frac{22}{7}\right]

Worked solution (try it first)
  1. The circumference is πd=227×42=132\pi d = \frac{22}{7} \times 42 = 132 cm.
  2. The arc is 60360=16\frac{60}{360} = \frac16 of it: 132÷6=22132 \div 6 = 22 cm, option A.

Report a problem with this question