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JAMB 1997 · UME · Q29

An arc of a circle subtends an angle of 70∘70^\circ at the centre. If the radius of the circle is 6 cm, calculate the area of the sector. [π=227]\left[\pi = \frac{22}{7}\right]

Worked solution (try it first)
  1. Area of a sector =θ360×πr2= \frac{\theta}{360} \times \pi r^2, with r2=36r^2 = 36.
  2. So the area is 70360×227×36\frac{70}{360} \times \frac{22}{7} \times 36.
  3. Cancel the 7 into 70 and the 36 into 360: 10×2210=22 cm2\frac{10 \times 22}{10} = 22\text{ cm}^2, option A.

Also set as JAMB 2015 · UTME · Q31

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