JAMB 2010 · UTME · Q17

If yy varies directly as the square root of xx and y=3y = 3 when x=16x = 16, calculate yy when x=64x = 64.

Worked solution (try it first)
  1. y=kxy = k\sqrt x.
  2. Put in y=3y = 3, x=16x = 16: 3=4k3 = 4k, so k=34k = \frac34.
  3. When x=64x = 64: y=34×8=6y = \frac34 \times 8 = 6, option C.

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