QuestionJAMBGeneral Maths2010ObjectiveSequences & series (AP, GP)Sequences & series (AP, GP)
The 3rd term of an arithmetic progression is −9 and the 7th term is −29. Find the 10th term of the progression.
Worked solution (try it first)
From the 3rd term to the 7th term is 4 steps of
d:
4d=−29−(−9)=−20, so
d=−5.
Go back two steps from the 3rd term:
a=−9−2(−5)=1.
The 10th term is
a+9d=1+9(−5)=−44, option C.
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