JAMB 2010 · UTME · Q40

If y=(2x+1)3y = (2x + 1)^3, find dydx\dfrac{dy}{dx}.

Worked solution (try it first)
  1. Chain rule: bring down the power 3 and reduce it by one, giving 3(2x+1)23(2x + 1)^2.
  2. Multiply by the derivative of the inside, 2x+12x + 1, which is 2: dydx=6(2x+1)2\frac{dy}{dx} = 6(2x + 1)^2, option D.

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