JAMB 2011 · UTME · Q19

Inequalities

Solve the inequality $-6(x + 3) \le 4(x - 2)$ .

Worked solution (try it first)

Expand both brackets: $-6x - 18 \le 4x - 8$ .
Add $6x$ and 8 to both sides: $-10 \le 10x$ .
Divide by 10: $-1 \le x$ , that is $x \ge -1$ , option B.

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