JAMB 2011 · UTME · Q20

Solve the inequality x2+2x>15x^2 + 2x > 15.

Worked solution (try it first)
  1. Bring everything to one side: x2+2x−15>0x^2 + 2x - 15 > 0.
  2. Factorise: (x+5)(x−3)>0(x + 5)(x - 3) > 0, so the roots are x=−5x = -5 and x=3x = 3.
  3. "Greater than 0" means outside the roots: x<−5x < -5 or x>3x > 3, option D.

Report a problem with this question