WAEC 2017 · Paper 2 · Q5

1. There are $\,{}^{13}C_5 = 1287$ committees.

(a)

1. All women: $\,{}^7C_5 = 21$, so $P = \dfrac{21}{1287}$
   $= \dfrac{7}{429}$
   $\approx 0.0163$.

(b)

1. 2 men and 3 women: $\,{}^6C_2 \times {}^7C_3 = 15 \times 35$
   $= 525$.
2. So $P = \dfrac{525}{1287}$
   $= \dfrac{175}{429}$
   $\approx 0.4079$.