WAEC 2019 · Paper 2 · Q11

  1. (a)

    Two linear transformations PP and QQ in the OxyOxy plane are defined by P:(x,y)→(x+2y,x)P : (x, y) \to (x + 2y, x) and Q:(x,y)→(x+y,−x+2y)Q : (x, y) \to (x + y, -x + 2y). Write down the matrices of PP and QQ.

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    P=(1210)P = \begin{pmatrix} 1 & 2 \\ 1 & 0 \end{pmatrix}, Q=(11−12)Q = \begin{pmatrix} 1 & 1 \\ -1 & 2 \end{pmatrix}

  2. (b)

    Find MM such that 2P+3Q−MQ=5I2P + 3Q - MQ = 5I, where MM is a 2×22 \times 2 matrix and II is the 2×22 \times 2 identity matrix.

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    M=(7373−1323)M = \begin{pmatrix} \frac73 & \frac73 \\ -\frac13 & \frac23 \end{pmatrix}

Worked solution (try it first)

(a)

  1. P=(1210)P = \begin{pmatrix} 1 & 2 \\ 1 & 0 \end{pmatrix} and Q=(11−12)Q = \begin{pmatrix} 1 & 1 \\ -1 & 2 \end{pmatrix}.

(b)

  1. Rearrange: MQ=2P+3Q−5IMQ = 2P + 3Q - 5I
    =(57−16)−(5005)= \begin{pmatrix} 5 & 7 \\ -1 & 6 \end{pmatrix} - \begin{pmatrix} 5 & 0 \\ 0 & 5 \end{pmatrix}
    =(07−11)= \begin{pmatrix} 0 & 7 \\ -1 & 1 \end{pmatrix}.
  2. ∣Q∣=2+1=3|Q| = 2 + 1 = 3, so Q−1=13(2−111)Q^{-1} = \frac13\begin{pmatrix} 2 & -1 \\ 1 & 1 \end{pmatrix}.
  3. Multiply on the right by Q−1Q^{-1}: M=(07−11)Q−1M = \begin{pmatrix} 0 & 7 \\ -1 & 1 \end{pmatrix}Q^{-1}
    =13(77−12)= \frac13\begin{pmatrix} 7 & 7 \\ -1 & 2 \end{pmatrix}.

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