WAEC 2015 · Paper 2 · Q2

  1. (a)

    Solve the inequality 4+34(x+2)≤38x+14 + \frac34(x + 2) \le \frac38x + 1.

    Show the answer

    x≤−12x \le -12

  2. (b)

    The diagram shows a rectangle PQRSPQRS, 20 cm20\text{ cm} high, from which a square of side x cmx\text{ cm} has been cut out of the middle of the base, leaving 10 cm10\text{ cm} on each side. If the area of the shaded portion is 484 cm2484\text{ cm}^2, find the values of xx.

    20 cm10 cm10 cmx cmx cmPQRS

    Separate values with commas, e.g. 3, −2

Worked solution (try it first)

(a)

  1. The denominators are 4 and 8, so multiply every term by 8: 32+6(x+2)≤3x+832 + 6(x + 2) \le 3x + 8.
  2. Expand: 32+6x+12≤3x+832 + 6x + 12 \le 3x + 8, so 6x+44≤3x+86x + 44 \le 3x + 8.
  3. Collect: 3x≤−363x \le -36, so x≤−12x \le -12.

(b)

  1. The rectangle is 20 cm high and 10+x+10=20+x10 + x + 10 = 20 + x cm wide.
  2. The shaded area is the rectangle without the square: 20(20+x)−x2=48420(20 + x) - x^2 = 484.
  3. Expand: 400+20x−x2=484400 + 20x - x^2 = 484, so x2−20x+84=0x^2 - 20x + 84 = 0.
  4. Factorise: (x−6)(x−14)=0(x - 6)(x - 14) = 0, so x=6x = 6 or x=14x = 14.

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