WAEC 2018 · Paper 2 · Q2

  1. (a)

    The graph of y=2px2−p2x−14y = 2px^2 - p^2x - 14 passes through the point (3,10)(3, 10). Find the values of pp.

    Separate values with commas, e.g. 3, −2

  2. (b)

    Two lines, 3y−2x=213y - 2x = 21 and 4y+5x=54y + 5x = 5, intersect at the point QQ. Find the coordinates of QQ.

    Separate values with commas, e.g. 3, −2

Worked solution (try it first)

(a)

  1. The point (3,10)(3, 10) is on the graph, so x=3x = 3 and y=10y = 10 satisfy the equation: 10=2p(9)−p2(3)−1410 = 2p(9) - p^2(3) - 14.
  2. So 10=18p−3p2−1410 = 18p - 3p^2 - 14, which rearranges to 3p2−18p+24=03p^2 - 18p + 24 = 0.
  3. Divide by 3: p2−6p+8=0p^2 - 6p + 8 = 0.
  4. Factorise: (p−2)(p−4)=0(p - 2)(p - 4) = 0.
  5. So p=2p = 2 or p=4p = 4.

(b)

  1. QQ is on both lines, so solve the equations simultaneously.
  2. Arrange them with xx first: −2x+3y=21-2x + 3y = 21 (1) and 5x+4y=55x + 4y = 5 (2).
  3. Multiply (1) by 4 and (2) by 3 so the yy terms match: −8x+12y=84-8x + 12y = 84 and 15x+12y=1515x + 12y = 15.
  4. Take the first from the second: 23x=−6923x = -69, so x=−3x = -3.
  5. From (1): 6+3y=216 + 3y = 21, so y=5y = 5.
  6. QQ is the point (−3,5)(-3, 5).

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