Quadratics & their graphs · Lesson 1 of 6

The shape of a quadratic

What y = ax² + bx + c looks like, what a, b and c each do to the curve, and why the roots are where it meets the x-axis.

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  3. 3
  4. 4
  5. 5
  6. 6

A quadratic is an expression whose highest power of xx is x2x^2, like x2−x−6x^2 - x - 6 or 2x2+3x−52x^2 + 3x - 5. We usually write it as

y=ax2+bx+cy = ax^2 + bx + c

where aa, bb and cc are numbers and aa is not 0. Before solving quadratics, it helps to see one. Every quadratic draws the same kind of curve, called a parabola.

See it for yourself

The shape of a quadraticMove the sliders

y = x² − x − 6

−7−5−3−11357−12−8−44812xyvertex
−2 and 3roots (y = 0)(0.5, −6.25)vertex (minimum)(0, −6)y-intercept
  • Turn the curve upside down
  • Move the curve so it never meets the x-axis
  • Make it just touch the x-axis at one point
  • Make the roots 2 and −3
The curve crosses the x-axis at x = −2 and x = 3: these are the roots, the solutions of x² − x − 6 = 0. It opens upwards, so the vertex is its lowest point (a minimum), halfway between the roots on the line x = 0.5.

Work through the challenges on the board. Try to predict which slider to move before you touch it.

What each number does

  • aa decides the shape. If aa is positive the curve opens upwards like a cup, so it has a lowest point. If aa is negative it opens downwards, with a highest point. The bigger aa is (ignoring the sign), the narrower the curve.
  • cc is where the curve cuts the yy-axis. Put x=0x = 0 into y=ax2+bx+cy = ax^2 + bx + c and everything disappears except cc. So the curve always passes through (0,c)(0, c).
  • bb slides the curve sideways (and up or down with it). You’ll see exactly how in lesson 3.

Roots: where the curve meets the x-axis

On the xx-axis, y=0y = 0. So the points where the curve meets the xx-axis are the values of xx that make ax2+bx+c=0ax^2 + bx + c = 0. These are called the roots of the equation (or its solutions).

Between its two roots the curve stays on one side of the xx-axis. For y=x2−x−6y = x^2 - x - 6 (a cup shape), the curve is below the axis between x=−2x = -2 and x=3x = 3, so y<0y < 0 there, and above it outside. That is how a quadratic inequality is solved: find the roots, then read which side you need (more in inequalities).

The vertex and the line of symmetry

A parabola is symmetrical. The line down its middle is the line of symmetry, and the curve turns round on it at the vertex (its lowest or highest point). When there are two roots, the line of symmetry is exactly halfway between them.

Your turn

JAMB 1986 · UME · Q23

The curve y=−x2+3x+4y = -x^2 + 3x + 4 intersects the coordinate axes at

Worked solution (try it first)
  1. On the yy-axis x=0x = 0, so y=4y = 4.
  2. The point is (0,4)(0, 4).
  3. On the xx-axis y=0y = 0: −x2+3x+4=0-x^2 + 3x + 4 = 0.
  4. Multiply by −1-1: x2−3x−4=0x^2 - 3x - 4 = 0.
  5. Factorise: (x−4)(x+1)=0(x - 4)(x + 1) = 0, so x=4x = 4 or x=−1x = -1.
  6. So the points are (0,4)(0, 4), (4,0)(4, 0) and (−1,0)(-1, 0), option D.

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