WAEC 2018 · Paper 2 · Q3

  1. (a)

    The diagonals of a rhombus are 10.2 cm10.2\text{ cm} and 9.3 cm9.3\text{ cm} long. Calculate, correct to one decimal place, the perimeter of the rhombus.

  2. (b)

    Given that sin⁡x=35\sin x = \frac35, 0∘<x<90∘0^\circ < x < 90^\circ, find the value of 5cos⁡x−4tan⁡x5\cos x - 4\tan x.

Worked solution (try it first)

(a)

  1. The diagonals of a rhombus cut each other in half at right angles.
  2. So each side is the hypotenuse of a right-angled triangle with legs 10.22=5.1\frac{10.2}{2} = 5.1 cm and 9.32=4.65\frac{9.3}{2} = 4.65 cm.
  3. Side =5.12+4.652= \sqrt{5.1^2 + 4.65^2}
    =26.01+21.6225= \sqrt{26.01 + 21.6225}
    =47.6325= \sqrt{47.6325}
    ≈6.902\approx 6.902 cm.
  4. The four sides are equal, so the perimeter is 4×6.902≈27.64 \times 6.902 \approx 27.6 cm.

(b)

  1. sin⁡x=35\sin x = \frac35 gives a right-angled triangle with sides 3, 4 and 5, so cos⁡x=45\cos x = \frac45 and tan⁡x=34\tan x = \frac34.
  2. Then 5cos⁡x−4tan⁡x=5×45−4×345\cos x - 4\tan x = 5 \times \frac45 - 4 \times \frac34
    =4−3= 4 - 3
    =1= 1.

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