WAEC 2019 · Paper 1 · Q3

Linear & simultaneous equations

Solve $\dfrac{y + 1}{2} - \dfrac{2y - 1}{3} = 4$ .

Worked solution (try it first)

Multiply every term by 6, the LCM of 2 and 3: $3(y + 1) - 2(2y - 1) = 24$ .
Expand, taking care with the minus: $3y + 3 - 4y + 2 = 24$ , so $-y + 5 = 24$ .
Take 5 from both sides: $-y = 19$ .
Multiply by $-1$ : $y = -19$ , option B.

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