QuestionWAECGeneral Maths2019ObjectiveApproximation & errorQuadratics & their graphsApproximation & error, Quadratics & their graphs
Simplify, correct to three significant figures, (27.63)2−(12.37)2.
Worked solution (try it first)
Use the difference of two squares:
a2−b2=(a−b)(a+b).
Here
a−b=27.63−12.37=15.26 and
a+b=40, so the value is
15.26×40=610.4.
To 3 significant figures the 0 is the third figure and the next figure is 4, so round down: 610, option D.
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