WAEC 2019 · Paper 1 · Q40

In the same diagram (RTRT a tangent at RR, ∠PQR=70∘\angle PQR = 70^\circ, ∠QRT=52∘\angle QRT = 52^\circ), find the value of x=∠PRQx = \angle PRQ.

70°52°yxRQPST
Worked solution (try it first)
  1. Alternate segment: ∠QPR\angle QPR also stands on chord QRQR, so ∠QPR=∠QRT=52∘\angle QPR = \angle QRT = 52^\circ.
  2. The angles of triangle PQRPQR add up to 180∘180^\circ: x=180∘−70∘−52∘x = 180^\circ - 70^\circ - 52^\circ
    =58∘= 58^\circ, option B.

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