WAEC 2021 · Paper 1 · Q38

Given that sin⁡x=35\sin x = \frac35, 0∘≤x≤90∘0^\circ \le x \le 90^\circ, evaluate (tan⁡x+2cos⁡x)(\tan x + 2\cos x).

Worked solution (try it first)
  1. sin⁡x=35\sin x = \frac35 gives a triangle with opposite 3 and hypotenuse 5.
  2. Pythagoras gives the adjacent side 25−9=4\sqrt{25 - 9} = 4.
  3. So cos⁡x=45\cos x = \frac45 and tan⁡x=34\tan x = \frac34.
  4. Then tan⁡x+2cos⁡x=34+85\tan x + 2\cos x = \frac34 + \frac85.
  5. Over 20 this is 1520+3220=4720\frac{15}{20} + \frac{32}{20} = \frac{47}{20}.
  6. As a mixed number, 4720=2720\frac{47}{20} = 2\frac{7}{20}, option C.

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