QuestionWAECGeneral Maths2022ObjectiveInequalitiesInequalities
WAEC 2022 · Paper 1 · Q37
Solve 4y+2−3y−1>1.
Worked solution (try it first)
Multiply every term by 12, the LCM of 4 and 3:
3(y+2)−4(y−1)>12.
Expand, taking care with the minus:
3y+6−4y+4>12, so
−y+10>12.
Subtract 10 from both sides:
−y>2.
Multiply by
−1 and reverse the sign:
y<−2, option B.
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