Flashcards · 14 cards

Solid mensuration

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  1. Rule

    The volume of a prism?

    Answer

    Area of the cross-section × length.

    Alength
  2. Rule

    The volume and curved surface area of a cylinder?

    Answer

    V=πr2hV = \pi r^2 h and curved surface =2πrh= 2\pi rh. Add πr2\pi r^2 for each closed end.

    rh
  3. Know it

    Surface area: how many circular ends for a closed can, a tank open at the top, and a pipe open at both ends?

    Answer

    Closed can: 2. Open-topped tank: 1. Pipe open at both ends: none.

  4. Rule

    The volume of metal in a pipe?

    Answer

    The ring between the two circles, times the length: π(R2−r2)h\pi(R^2 - r^2)h.

    Rrmetal in the pipe= outer − inner= π(R² − r²) × length
    The end of a pipeThe metal is the ring between the two circles, all the way along
  5. Rule

    The longest diagonal of a cuboid l×b×hl \times b \times h?

    Answer

    Pythagoras twice: l2+b2+h2\sqrt{l^2 + b^2 + h^2}.

    lbhdd² = l² + b² + h²
    Pythagoras twiceFloor diagonal first, then up to the opposite top corner
  6. Rule

    The volume of a cone, and of a pyramid?

    Answer

    13×\frac13 \times base area ×\times height. For a cone, 13πr2h\frac13\pi r^2 h.

    hrl
  7. Rule

    In a cone, how are hh, rr and the slant height ll related? Which does each formula use?

    Answer

    l2=h2+r2l^2 = h^2 + r^2. The volume uses hh; the curved surface πrl\pi rl uses ll.

    hrll² = r² + h²
    Height, radius, slant heightA right-angled triangle inside every cone
  8. Rule

    A sector is bent into a cone. What becomes what?

    Answer

    The sector's radius becomes the slant height; its arc becomes the circumference of the base.

    θllarc → base circler = θ ÷ 360 × l
    Bending a sectorThe radius becomes the slant height; the arc becomes the base circle
  9. Rule

    The volume and surface area of a sphere?

    Answer

    V=43πr3V = \frac43\pi r^3 and S=4πr2S = 4\pi r^2. A hemisphere holds half: 23πr3\frac23\pi r^3.

    r
  10. Rule

    How do you find the volume of a frustum?

    Answer

    Put the tip back: the volume of the big cone minus the small cone cut off.

    rRhlR − rHl² = h² + (R − r)²
    A frustumPut the tip back to find H; the slant height comes from the small triangle
  11. Rule

    Similar solids with lengths in the ratio kk: how do areas and volumes compare?

    Answer

    Areas × k2k^2, volumes × k3k^3.

    side 1side 2lengths × 2, areas × 4, volumes × 8
    Similar solidsLengths × k, areas × k², volumes × k³
  12. Know it

    How many litres are in 1 m³? How many cm³ in a litre?

    Answer

    1 m³ = 1000 litres, and 1 litre = 1000 cm³. Change to one unit before you divide.

  13. Which method?

    WAEC 2022 · Paper 2 · Q8 (b)

    A sector of angle 220∘220^\circ is removed from a thin circular metal sheet of radius 63 cm63\text{ cm}. It is then folded with the straight edges meeting to form a right circular cone. Calculate, correct to one decimal place, the: (i) base radius; (ii) volume, of the cone. [Take π=227]\left[\text{Take }\pi = \frac{22}{7}\right]

    How do you find the cone's radius?

    Answer

    The sector's arc becomes the base circumference: 220360×2π×63=2πr\frac{220}{360} \times 2\pi \times 63 = 2\pi r, so r=220360×63r = \frac{220}{360} \times 63. The 63 cm becomes the slant height.

  14. Which method?

    WAEC 2020 · Paper 2 · Q7 (a)

    The diagram shows a wooden structure in the form of a cone, mounted on a hemispherical base. The vertical height of the cone is 48 m48\text{ m} and the base radius is 14 m14\text{ m}. Calculate, correct to three significant figures, the surface area of the structure. [Take π=227]\left[\text{Take }\pi = \frac{22}{7}\right]

    48 m14 mLMN
    Which surfaces count?

    Answer

    Only the outside: the cone's curved surface (πrl\pi rl, with ll from Pythagoras) and the hemisphere's curved surface (2πr22\pi r^2). The circle where they join is hidden.