JAMB 2010 · UTME · Q19

For what range of values of $x$ is $\frac12x + \frac14 > \frac13x + \frac12$ ?

Worked solution (try it first)

Subtract $\frac13x$ and $\frac14$ from both sides: $\frac12x - \frac13x > \frac12 - \frac14$ .
Simplify each side: $\frac16x > \frac14$ .
Multiply both sides by 6: $x > \frac64$ , which is $\frac32$ .
So option B.