JAMB 2010 · UTME · Q31

If the two smaller sides of a right-angled triangle are 4 cm4\text{ cm} and 5 cm5\text{ cm}, find its area.

Worked solution (try it first)
  1. The two smaller sides of a right-angled triangle are the ones that meet at the right angle, so one is the base and the other the height.
  2. Area =12×base×height= \frac12 \times \text{base} \times \text{height}
    =12×4×5= \frac12 \times 4 \times 5
    =10 cm2= 10\text{ cm}^2, option A.

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