JAMB 2010 · UTME · Q32

Plane mensuration

An arc subtends an angle of $50^\circ$ at the centre of a circle of radius $6\text{ cm}$ . Calculate the area of the sector formed. $\left[\text{Take }\pi = \frac{22}{7}\right]$

Worked solution (try it first)

Area of a sector $= \frac{\theta}{360} \times \pi r^2$
$= \frac{50}{360} \times \frac{22}{7} \times 36$ .
Simplify $\frac{50 \times 36}{360} = 5$ , so the area is $5 \times \frac{22}{7} = \frac{110}{7}\text{ cm}^2$ , option B.

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