WAEC 2019 · Paper 2 · Q3

  1. (a)

    A binary operation ∗* is defined on the set of real numbers, R\mathbb R, by x∗y=x+y−3xyx * y = x + y - 3xy, where x,y∈Rx, y \in \mathbb R. Find the identity element in R\mathbb R under the operation ∗*.

  2. (b)

    Find the range of values of nn for which 3+14n−5n2≤03 + 14n - 5n^2 \le 0.

    Show the answer

    n≤−15n \le -\frac15 or n≥3n \ge 3

Worked solution (try it first)

(a)

  1. The identity ee satisfies x∗e=xx * e = x: x+e−3xe=xx + e - 3xe = x.
  2. Take xx from both sides: e−3xe=0e - 3xe = 0, so e(1−3x)=0e(1 - 3x) = 0.
  3. This must hold for every xx, so e=0e = 0.
  4. Check: x∗0=x+0−0=xx * 0 = x + 0 - 0 = x ✓.

(b)

  1. Make the n2n^2 term positive: multiply by −1-1 and turn the sign round: 5n2−14n−3≥05n^2 - 14n - 3 \ge 0.
  2. Factorise: two numbers that multiply to 5×(−3)=−155 \times (-3) = -15 and add to −14-14 are −15-15 and 1.
  3. So 5n2−15n+n−3=5n(n−3)+1(n−3)5n^2 - 15n + n - 3 = 5n(n - 3) + 1(n - 3)
    =(5n+1)(n−3)≥0= (5n + 1)(n - 3) \ge 0.
  4. The roots are n=−15n = -\frac15 and n=3n = 3. "≥0\ge 0" is outside them: n≤−15n \le -\frac15 or n≥3n \ge 3.
  5. Check with n=0n = 0, between the roots: 3+0−0=33 + 0 - 0 = 3, which is not ≤0\le 0 ✓.

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