WAEC 2019 · Paper 1 · Q38

In the diagram, OO is the centre of the circle of radius 18 cm18\text{ cm}. If ∠ZXY=70∘\angle ZXY = 70^\circ, calculate the length of arc ZYZY. [Take π=227]\left[\text{Take }\pi = \frac{22}{7}\right]

18 cm70°OXZY
Worked solution (try it first)
  1. ∠ZXY\angle ZXY is at the circumference on arc ZYZY.
  2. The angle at the centre is twice it: ∠ZOY=140∘\angle ZOY = 140^\circ.
  3. Arc length is θ360∘×2πr\frac{\theta}{360^\circ} \times 2\pi r: arc ZY=140360×2×227×18ZY = \frac{140}{360} \times 2 \times \frac{22}{7} \times 18.
  4. That is 44 cm, option C.

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