WAEC 2021 · Paper 1 · Q45

A box contains 40 identical balls of which 10 are red and 12 are blue. A ball is selected at random. What is the probability that it is neither red nor blue?

Worked solution (try it first)
  1. Red and blue together are 10+12=2210 + 12 = 22 balls.
  2. Neither red nor blue leaves 40−22=1840 - 22 = 18 balls.
  3. So the probability is 1840=920\frac{18}{40} = \frac{9}{20}, option A.

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