WAEC 2021 · Paper 1 · Q46

A fair die is tossed twice. What is the probability of getting a sum of at least 10?

Worked solution (try it first)

Tossing a die twice gives 36 equally likely outcomes.
A sum of at least 10 comes from $(4, 6), (5, 5), (6, 4), (5, 6), (6, 5), (6, 6)$ , which is 6 outcomes.
So the probability is $\frac{6}{36} = \frac16$ , option D.